QUESTION IMAGE
Question
factoring trinomials (a = 1)
factor each completely.
- $b^2 + 8b + 7$
- $n^2 - 11n + 10$
- $m^2 + m - 90$
- $n^2 + 4n - 12$
- $n^2 - 10n + 9$
- $b^2 + 16b + 64$
- $m^2 + 2m - 24$
- $x^2 - 4x + 24$
- $k^2 - 13k + 40$
- $a^2 + 11a + 18$
- $n^2 - n - 56$
- $n^2 - 5n + 6$
1) Step1: Find factors of 7 summing to 8
Factors are 1 and 7.
1) Step2: Write factored form
$(b+1)(b+7)$
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2) Step1: Find factors of 10 summing to -11
Factors are -1 and -10.
2) Step2: Write factored form
$(n-1)(n-10)$
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3) Step1: Find factors of -90 summing to 1
Factors are 10 and -9.
3) Step2: Write factored form
$(m+10)(m-9)$
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4) Step1: Find factors of -12 summing to 4
Factors are 6 and -2.
4) Step2: Write factored form
$(n+6)(n-2)$
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5) Step1: Find factors of 9 summing to -10
Factors are -1 and -9.
5) Step2: Write factored form
$(n-1)(n-9)$
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6) Step1: Identify perfect square trinomial
$b^2+16b+64 = b^2+2(8b)+8^2$
6) Step2: Write factored form
$(b+8)^2$
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7) Step1: Find factors of -24 summing to 2
Factors are 6 and -4.
7) Step2: Write factored form
$(m+6)(m-4)$
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8) Step1: Check discriminant for factorization
Discriminant: $(-4)^2-4(1)(24)=16-96=-80<0$
8) Step2: State non-factorability over reals
Trinomial is prime (cannot be factored over real numbers)
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9) Step1: Find factors of 40 summing to -13
Factors are -5 and -8.
9) Step2: Write factored form
$(k-5)(k-8)$
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10) Step1: Find factors of 18 summing to 11
Factors are 2 and 9.
10) Step2: Write factored form
$(a+2)(a+9)$
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11) Step1: Find factors of -56 summing to -1
Factors are -8 and 7.
11) Step2: Write factored form
$(n-8)(n+7)$
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12) Step1: Find factors of 6 summing to -5
Factors are -2 and -3.
12) Step2: Write factored form
$(n-2)(n-3)$
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- $\boldsymbol{(b+1)(b+7)}$
- $\boldsymbol{(n-1)(n-10)}$
- $\boldsymbol{(m+10)(m-9)}$
- $\boldsymbol{(n+6)(n-2)}$
- $\boldsymbol{(n-1)(n-9)}$
- $\boldsymbol{(b+8)^2}$
- $\boldsymbol{(m+6)(m-4)}$
- $\boldsymbol{\text{Prime (cannot be factored over real numbers)}}$
- $\boldsymbol{(k-5)(k-8)}$
- $\boldsymbol{(a+2)(a+9)}$
- $\boldsymbol{(n-8)(n+7)}$
- $\boldsymbol{(n-2)(n-3)}$