Question

a fair coin is tossed two times in succession. the set of equally likely outcomes is {hh, ht, th, tt}. find the probability of getting exactly one tail. the probability of getting one tail is (type an integer or a simplified fraction.)

Explanation:

Step1: Identify favorable outcomes

Outcomes with exactly one tail: HT, TH. So 2 favorable outcomes.

Step2: Total possible outcomes

Total outcomes: 4 (HH, HT, TH, TT).

Step3: Calculate probability

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$ = $\frac{2}{4}$ = $\frac{1}{2}$.

Answer:

$\frac{1}{2}$