Question

1. in the figure, $jk = 5x + 7$, $kl = 7x + 2$ and $jl = 45$.

6a find $x$.
$x=3$
6b find $kl$.
$kl = \square$

Explanation:

Step1: Substitute x=3 into KL formula

$KL = 7(3) + 2$

Step2: Calculate the product first

$7(3) = 21$

Step3: Add the remaining term

$21 + 2 = 23$

Answer:

23