QUESTION IMAGE
Question
in the figure below, (mangle abd = 66^{circ}), and (mangle2) is two times (mangle1). find (mangle1).
Step1: Set up an equation
Let $m\angle1 = x$. Then $m\angle2 = 2x$. Since $m\angle ABD=m\angle1 + m\angle2$, we have $66^{\circ}=x + 2x$.
Step2: Simplify the equation
Combine like - terms: $66^{\circ}=3x$.
Step3: Solve for x
Divide both sides of the equation by 3: $x=\frac{66^{\circ}}{3}=22^{\circ}$.
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$22$