QUESTION IMAGE
Question
for the figure shown, find m∠1. (the figure is not drawn to scale.) m∠1 =
Step1: Recall angle - sum property of a triangle
The sum of the interior angles of a triangle is 180°. Let the third - interior angle of the triangle be \(x\). Then \(x + 62^{\circ}+57^{\circ}=180^{\circ}\).
Step2: Calculate the third - interior angle
\[
$$\begin{align*}
x&=180^{\circ}-(62^{\circ} + 57^{\circ})\\
x&=180^{\circ}-119^{\circ}\\
x& = 61^{\circ}
\end{align*}$$
\]
Step3: Use the linear - pair property
\(\angle1\) and the third - interior angle of the triangle form a linear pair. A linear pair of angles sums to 180°. So \(m\angle1=180^{\circ}-61^{\circ}\).
Step4: Calculate \(m\angle1\)
\(m\angle1 = 119^{\circ}\)
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\(119\)