QUESTION IMAGE
Question
figure surface area
- cylinder: height 40 m, base diameter 26 m, find its surface area
- cylinder: height 4 mm, base radius 10 mm, find its surface area
- cylinder: height 26 yd, base radius 11 yd, find its surface area
The total surface area of a cylinder is given by the formula:
$$SA = 2\pi r^2 + 2\pi rh = 2\pi r(r + h)$$
where $r$ is the radius and $h$ is the height of the cylinder.
---
Cylinder 1 (26 m diameter, 40 m height)
Step1: Calculate the radius
Diameter $d=26\ \text{m}$, so $r=\frac{d}{2}=\frac{26}{2}=13\ \text{m}$
Step2: Plug values into formula
$$\begin{align*}
SA&=2\pi(13)^2 + 2\pi(13)(40)\\
&=2\pi(169) + 2\pi(520)\\
&=338\pi + 1040\pi\\
&=1378\pi\\
&\approx1378\times3.14\\
&=4354.28\ \text{m}^2
\end{align*}$$
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Cylinder 2 (10 mm radius, 4 mm height)
Step1: Use given radius $r=10\ \text{mm}$, $h=4\ \text{mm}$
Step2: Plug values into formula
$$\begin{align*}
SA&=2\pi(10)^2 + 2\pi(10)(4)\\
&=2\pi(100) + 2\pi(40)\\
&=200\pi + 80\pi\\
&=280\pi\\
&\approx280\times3.14\\
&=879.2\ \text{mm}^2
\end{align*}$$
---
Cylinder 3 (11 yd radius, 26 yd height)
Step1: Use given radius $r=11\ \text{yd}$, $h=26\ \text{yd}$
Step2: Plug values into formula
$$\begin{align*}
SA&=2\pi(11)^2 + 2\pi(11)(26)\\
&=2\pi(121) + 2\pi(286)\\
&=242\pi + 572\pi\\
&=814\pi\\
&\approx814\times3.14\\
&=2584.92\ \text{yd}^2
\end{align*}$$
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- $\boldsymbol{4354.28\ \text{m}^2}$
- $\boldsymbol{879.2\ \text{mm}^2}$
- $\boldsymbol{2584.92\ \text{yd}^2}$