Question

fill in the table using this function rule. ( y = -5x - 1 ) table with ( x ) values ( -1, 0, 1, 2 ) and empty ( y ) cells

Explanation:

Step1: When \( x = -1 \)

Substitute \( x = -1 \) into \( y = -5x - 1 \).
\( y = -5\times(-1) - 1 = 5 - 1 = 4 \)

Step2: When \( x = 0 \)

Substitute \( x = 0 \) into \( y = -5x - 1 \).
\( y = -5\times0 - 1 = 0 - 1 = -1 \)

Step3: When \( x = 1 \)

Substitute \( x = 1 \) into \( y = -5x - 1 \).
\( y = -5\times1 - 1 = -5 - 1 = -6 \)

Step4: When \( x = 2 \)

Substitute \( x = 2 \) into \( y = -5x - 1 \).
\( y = -5\times2 - 1 = -10 - 1 = -11 \)

Answer:

When \( x = -1 \), \( y = 4 \); when \( x = 0 \), \( y = -1 \); when \( x = 1 \), \( y = -6 \); when \( x = 2 \), \( y = -11 \)

So the filled table (rows from top to bottom for \( y \)): \( 4 \), \( -1 \), \( -6 \), \( -11 \)