Question

fill in the table using this function rule.
y = 5x + 1
table with columns x (values: -2, 0, 2, 4) and y (empty cells); two buttons (refresh, ×) on the right

Explanation:

Step1: Substitute \( x = -2 \) into \( y = 5x + 1 \)

\( y = 5\times(-2)+1 = -10 + 1 = -9 \)

Step2: Substitute \( x = 0 \) into \( y = 5x + 1 \)

\( y = 5\times0 + 1 = 0 + 1 = 1 \)

Step3: Substitute \( x = 2 \) into \( y = 5x + 1 \)

\( y = 5\times2 + 1 = 10 + 1 = 11 \)

Step4: Substitute \( x = 4 \) into \( y = 5x + 1 \)

\( y = 5\times4 + 1 = 20 + 1 = 21 \)

Answer:

When \( x = -2 \), \( y = -9 \); when \( x = 0 \), \( y = 1 \); when \( x = 2 \), \( y = 11 \); when \( x = 4 \), \( y = 21 \)

The filled table is:

\( x \)	\( y \)
0	1
2	11
4	21