Question

fill in the table using this function rule.
( y = 6x - 3 )
table with columns x and y, rows for x=1, 2, 3, 10 with empty y cells

Explanation:

Step1: Substitute \( x = 1 \) into \( y = 6x - 3 \)

\( y = 6(1) - 3 = 6 - 3 = 3 \)

Step2: Substitute \( x = 2 \) into \( y = 6x - 3 \)

\( y = 6(2) - 3 = 12 - 3 = 9 \)

Step3: Substitute \( x = 3 \) into \( y = 6x - 3 \)

\( y = 6(3) - 3 = 18 - 3 = 15 \)

Step4: Substitute \( x = 10 \) into \( y = 6x - 3 \)

\( y = 6(10) - 3 = 60 - 3 = 57 \)

Answer:

When \( x = 1 \), \( y = 3 \); when \( x = 2 \), \( y = 9 \); when \( x = 3 \), \( y = 15 \); when \( x = 10 \), \( y = 57 \)

The filled table is:

\( x \)	\( y \)
2	9
3	15
10	57