Question

find f(x)
f(x)=\frac{8}{9x^{3}}
f(x)=square

Explanation:

Step1: Rewrite the function

$f(x)=\frac{8}{9}x^{-3}$

Step2: Apply power - rule for derivatives

$f'(x)=\frac{8}{9}\times(-3)x^{-3 - 1}$

Step3: Simplify the expression

$f'(x)=-\frac{8}{3}x^{-4}=-\frac{8}{3x^{4}}$

Answer:

$-\frac{8}{3x^{4}}$