Question

find all angles θ between 0° and 180° satisfying the given equation. (enter your answers as a comma - separated list.) sin(θ) = $\frac{sqrt{3}}{2}$ θ = 。 resources read it submit answer

Explanation:

Step1: Recall sine - value of special angles

We know that $\sin(60^{\circ})=\frac{\sqrt{3}}{2}$ and the sine function $y = \sin\theta$ is positive in the first and second quadrants for $0^{\circ}\leq\theta\leq180^{\circ}$.

Step2: Find angles in the given range

In the first - quadrant, $\theta_1 = 60^{\circ}$. In the second - quadrant, $\theta_2=180^{\circ}-60^{\circ}=120^{\circ}$.

Answer:

$60^{\circ},120^{\circ}$