Question

(a) find the area of the following (in square units).
the light rectangle (on the top): 24
the dark rectangle (on the bottom): $3x$

(b) give the area of the entire figure (in square units) in two different ways.
as a sum of two areas: $24 + 3x$
as a product of the length and width: □

Explanation:

Step1: Find height of light rectangle

The area of the light rectangle is 24, and its width is 3. Using the area formula for a rectangle $A = l \times w$, solve for height:
$\text{Height} = \frac{24}{3} = 8$

Step2: Find total height of figure

Add the height of the light rectangle and the height of the dark rectangle:
$\text{Total height} = 8 + x$

Step3: Write area as length×width

The width of the entire figure is 3, and total height is $8+x$. The area is the product of these two:
$3 \times (8 + x)$

Answer:

$3(8+x)$