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find the area of a triangle with side lengths 3, 4, and 5. 12 6 36 24

Question

find the area of a triangle with side lengths 3, 4, and 5.
12
6
36
24

Explanation:

Step1: Identify the type of triangle

Since $3^{2}+4^{2}=5^{2}$ (i.e., $9 + 16=25$), it is a right - triangle with legs of lengths 3 and 4.

Step2: Apply the area formula for a right - triangle

The area formula for a right - triangle is $A=\frac{1}{2}ab$, where $a$ and $b$ are the lengths of the legs. Here, $a = 3$ and $b = 4$. So $A=\frac{1}{2}\times3\times4$.
$A=\frac{1}{2}\times3\times4=6$

Answer:

B. 6