Question

find the difference.
$(4x^3 - 12x^2 - 5) - (-8x^2 + 4x + 3) = \square$

Explanation:

Step1: Distribute the negative sign

$4x^3 - 12x^2 - 5 + 8x^2 - 4x - 3$

Step2: Combine like $x^2$ terms

$4x^3 + (-12x^2 + 8x^2) - 4x + (-5 - 3)$
$4x^3 - 4x^2 - 4x + (-5 - 3)$

Step3: Combine constant terms

$4x^3 - 4x^2 - 4x - 8$

Answer:

$4x^3 - 4x^2 - 4x - 8$