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find the differences. a. $\begin{array}{r}4,717\\ -1,812\\ hlineend{arr…

Question

find the differences.
a.
$\begin{array}{r}4,717\\ -1,812\\ hlineend{array}$
b.
$\begin{array}{r}8,261\\ -4,950\\ hlineend{array}$
c.
$\begin{array}{r}6,391\\ -1,87\\ hlineend{array}$
d.
$\begin{array}{r}9,491\\ -5,327\\ hlineend{array}$
e.
$\begin{array}{r}3,615\\ -2,271\\ hlineend{array}$
f.
$\begin{array}{r}7,535\\ -920\\ hlineend{array}$
g.
$\begin{array}{r}5,966\\ -3,485\\ hlineend{array}$
h.
$\begin{array}{r}3,167\\ -148\\ hlineend{array}$
i.
$\begin{array}{r}8,724\\ -5,913\\ hlineend{array}$
j.
$\begin{array}{r}6,193\\ -3,046\\ hlineend{array}$

Explanation:

Response
Part a

Step1: Align the numbers by place value

We have \(4717 - 1812\).

Step2: Subtract each place value

  • Units place: \(7 - 2 = 5\)
  • Tens place: \(1 - 1 = 0\)
  • Hundreds place: \(7 - 8\), we need to borrow 1 from the thousands place. So \(17 - 8 = 9\), and the thousands place becomes \(4 - 1 = 3\)
  • Thousands place: \(3 - 1 = 2\)

So \(4717-1812 = 2905\)

Part b

Step1: Align the numbers by place value

We have \(8261 - 4950\).

Step2: Subtract each place value

  • Units place: \(1 - 0 = 1\)
  • Tens place: \(6 - 5 = 1\)
  • Hundreds place: \(2 - 9\), we need to borrow 1 from the thousands place. So \(12 - 9 = 3\), and the thousands place becomes \(8 - 1 = 7\)
  • Thousands place: \(7 - 4 = 3\)

So \(8261 - 4950=3311\)

Part c

Step1: Align the numbers by place value

We have \(6391 - 187\).

Step2: Subtract each place value

  • Units place: \(1 - 7\), we need to borrow 1 from the tens place. So \(11 - 7 = 4\), and the tens place becomes \(9 - 1 = 8\)
  • Tens place: \(8 - 8 = 0\)
  • Hundreds place: \(3 - 1 = 2\)
  • Thousands place: \(6 - 0 = 6\)

So \(6391-187 = 6204\)

Part d

Answer:

s:
a. \(2905\)
b. \(3311\)
c. \(6204\)
d. \(4164\)
e. \(1344\)
f. \(6615\)
g. \(2481\)
h. \(3019\)
i. \(2811\)
j. \(3147\)