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find the distance, d, of $overline{ab}$. a = (3, 7) b = (7, 11) d = ? d…

Question

find the distance, d, of $overline{ab}$. a = (3, 7) b = (7, 11) d = ? d = $sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$ round to the nearest tenth.

Explanation:

Step1: Identify coordinates

Let $(x_1,y_1)=(3,7)$ and $(x_2,y_2)=(7,11)$.

Step2: Substitute into distance formula

$d=\sqrt{(7 - 3)^2+(11 - 7)^2}=\sqrt{4^2+4^2}=\sqrt{16 + 16}=\sqrt{32}$.

Step3: Simplify and round

$\sqrt{32}\approx5.7$.

Answer:

$5.7$