Question

find the distance between x(-3,8) and z(-5,1). round to the nearest tenth, if necessary

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1=-3,y_1 = 8,x_2=-5,y_2 = 1$.

Step2: Calculate differences

First, find $x_2 - x_1$ and $y_2 - y_1$. $x_2 - x_1=-5-(-3)=-5 + 3=-2$ and $y_2 - y_1=1 - 8=-7$.

Step3: Square the differences

$(x_2 - x_1)^2=(-2)^2 = 4$ and $(y_2 - y_1)^2=(-7)^2 = 49$.

Step4: Sum the squared differences

$(x_2 - x_1)^2+(y_2 - y_1)^2=4 + 49=53$.

Step5: Calculate the distance

$d=\sqrt{53}\approx7.3$.

Answer:

$7.3$