Question

find the distance between b(3, -4) and c(5, -5). round to the nearest tenth, if necessary. about 8.2 units

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Given $B(3,-4)$ where $x_1 = 3,y_1=-4$ and $C(5,-5)$ where $x_2 = 5,y_2=-5$.

Step2: Substitute values

$d=\sqrt{(5 - 3)^2+(-5+4)^2}=\sqrt{(2)^2+(-1)^2}=\sqrt{4 + 1}=\sqrt{5}$.

Step3: Calculate and round

$\sqrt{5}\approx2.2$

Answer:

$2.2$