Question

find the force required to stop a 10kg cart that has been traveling 5m/s in 10seconds. 20n 1n 5n 10n

Explanation:

Step1: Calculate the acceleration

Use the formula $a=\frac{v - u}{t}$, where $v = 0m/s$ (final velocity as the cart stops), $u = 5m/s$ (initial velocity), and $t = 10s$ (time). So $a=\frac{0 - 5}{10}=- 0.5m/s^{2}$.

Step2: Calculate the force

Use Newton's second - law $F = ma$, where $m = 10kg$ (mass of the cart) and $a=-0.5m/s^{2}$. So $F=10\times(- 0.5)=-5N$. The magnitude of the force is $5N$.

Answer:

C. 5N