Question

find the x and y intercepts of this linear equation. 4x + 8y = 64 x-intercept ( ? , ) y-intercept (, )

Explanation:

Step1: Find x-intercept (set y=0)

Substitute $y=0$ into $4x + 8y = 64$:
$$4x + 8(0) = 64$$
$$4x = 64$$
$$x = \frac{64}{4} = 16$$
So x-intercept is $(16, 0)$.

Step2: Find y-intercept (set x=0)

Substitute $x=0$ into $4x + 8y = 64$:
$$4(0) + 8y = 64$$
$$8y = 64$$
$$y = \frac{64}{8} = 8$$
So y-intercept is $(0, 8)$.

Answer:

x-intercept: $(16, 0)$
y-intercept: $(0, 8)$