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find the largest angle of $\\triangle efg$. assume that $x$ is a positi…

Question

find the largest angle of $\triangle efg$. assume that $x$ is a positive number.

Explanation:

Step1: Recall the triangle side-angle relationship

In a triangle, the largest angle is opposite the longest side. So we first need to determine the longest side of \(\triangle EFG\).

The side lengths are \(33x\) (opposite \(\angle F\)), \(48x\) (opposite \(\angle G\)), and \(51x\) (opposite \(\angle E\)). Since \(x>0\), we can compare the coefficients: \(51>48>33\), so \(51x\) is the longest side.

Step2: Identify the angle opposite the longest side

The side \(51x\) is \(FG\), and the angle opposite \(FG\) is \(\angle E\) (because in \(\triangle EFG\), side \(FG\) is between \(F\) and \(G\), so the angle opposite is at \(E\)). By the side - angle relationship (larger side opposite larger angle), the angle opposite the longest side (\(51x\)) is the largest angle.

Answer:

The largest angle of \(\triangle EFG\) is \(\angle E\) (the angle opposite the side of length \(51x\)).