Question

find the mass of a cube that has a density of 2.7 g/ml and measures 3 cm on each side.

Explanation:

Step1: Calculate volume of cube

The volume $V$ of a cube with side length $a$ is given by $V = a^{3}$. Here $a = 3\ cm$. So $V=(3\ cm)^{3}=27\ cm^{3}$. Since $1\ cm^{3}=1\ mL$, the volume $V = 27\ mL$.

Step2: Use density - mass - volume formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. We know $
ho = 2.7\ g/mL$ and $V = 27\ mL$. Rearranging for mass $m$, we get $m=
ho\times V$.

Step3: Calculate mass

Substitute $
ho = 2.7\ g/mL$ and $V = 27\ mL$ into the formula $m=
ho\times V$. So $m=2.7\ g/mL\times27\ mL = 72.9\ g$.

Answer:

$72.9\ g$