QUESTION IMAGE
Question
find the missing number so that the equation has infinitely many solutions. -3(-x + 3) = 3x + \square
Step1: Expand left-hand side
$$\begin{align*}
-3(-x + 3) &= (-3)(-x) + (-3)(3)\\
&= 3x - 9
\end{align*}$$
Step2: Match constant terms
For infinitely many solutions, both sides of the equation must be identical. The right-hand side is $3x + \square$, so the constant term must equal $-9$.
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$-9$