Question

find the number of terms and the degree of this polynomial.\\(9j^2 - j - 1\\)\\(\\)number of terms:\\(\square\\)\\(\\)degree:\\(\square\\)

Explanation:

Step1: Identify terms in the polynomial

A term in a polynomial is a single number, variable, or the product of numbers and variables, separated by addition or subtraction. For the polynomial \(9j^2 - j - 1\), the terms are \(9j^2\), \(-j\), and \(-1\). So we count these terms.
Number of terms: \(3\)

Step2: Determine the degree of the polynomial

The degree of a polynomial is the highest power (exponent) of the variable in the polynomial. In \(9j^2 - j - 1\), the exponents of \(j\) are \(2\) (in \(9j^2\)), \(1\) (in \(-j\), since \(j = j^1\)), and \(0\) (in \(-1\), since \(-1 = -1j^0\)). The highest exponent is \(2\).
Degree: \(2\)

Answer:

Number of terms: \(3\)
Degree: \(2\)