Question

find the perimeter of the following shape, rounded to the nearest tenth: 8 11.3 12 17.9 check this box to submit your assessment for grading

Explanation:

Step1: Identify side - length using distance formula

The shape appears to be a rhombus. Let's assume two adjacent vertices, say \(A(x_1,y_1)\) and \(B(x_2,y_2)\). Using the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). If we consider the grid, assume \(A(- 1,2)\) and \(B(1,0)\). Then \(d=\sqrt{(1 + 1)^2+(0 - 2)^2}=\sqrt{4 + 4}=\sqrt{8}=2\sqrt{2}\).

Step2: Calculate perimeter

A rhombus has 4 equal - length sides. The perimeter \(P = 4d\). Substituting \(d = 2\sqrt{2}\), we get \(P=4\times2\sqrt{2}=8\sqrt{2}\approx8\times1.414 = 11.312\approx11.3\).

Answer:

11.3