Question

find (a) pq to the nearest tenth and (b) the coordinates of the mid - point of $overline{pq}$. p(4, - 6), q(3, - 2). (a) pq = $square$ (round to the nearest tenth as needed)

Explanation:

Step1: Recall distance formula

The distance formula between two points $P(x_1,y_1)$ and $Q(x_2,y_2)$ is $d(P,Q)=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1 = 4,y_1=-6,x_2 = 3,y_2=-2$.

Step2: Substitute values

$PQ=\sqrt{(3 - 4)^2+(-2+6)^2}=\sqrt{(-1)^2+4^2}=\sqrt{1 + 16}=\sqrt{17}\approx4.1$

Answer:

$4.1$