Question

find the quotient.\\(\frac{-9h^{4}+27h^{3}}{h^{2}} = \square\\)

Explanation:

Step1: Split the fraction

$\frac{-9h^4 + 27h^3}{h^2} = \frac{-9h^4}{h^2} + \frac{27h^3}{h^2}$

Step2: Simplify each term

For $\frac{-9h^4}{h^2}$: subtract exponents: $h^{4-2}=h^2$, so term is $-9h^2$
For $\frac{27h^3}{h^2}$: subtract exponents: $h^{3-2}=h^1=h$, so term is $27h$

Step3: Combine simplified terms

$-9h^2 + 27h$

Answer:

$-9h^2 + 27h$