Question

find the real solution(s) of the equation ((x + 10)^5 = 70). round your answer(s) to two decimal places.
(xapproxsquare)

Explanation:

Step1: Take 5th root of both sides

$$x + 10 = \sqrt[5]{70}$$

Step2: Isolate x by subtracting 10

$$x = \sqrt[5]{70} - 10$$

Step3: Calculate and round to 2 decimals

$\sqrt[5]{70} \approx 2.30$, so $x \approx 2.30 - 10$

Answer:

$x \approx -7.70$