Question

find the residuals for the second model, $y=2x-4$.
year 2010 2011 2012 2013 2014
residual -1 -1 -2 -3 -2.6
(type integers or decimals.)
the sum of the residuals for $y=2x-4$ is $-9.6$.
(type an integer or a decimal.)
(b) find the sum of the squares of the residuals for each model.
the sum of the squares of the residuals for $y=1.18x+2.23$ is $15.80$.
(round the final answer to two decimal places as needed. round all intermediate values to two decimal places as needed.)
the sum of the squares of the residuals for $y=2x-4$ is $21.76$.
(round the final answer to two decimal places as needed. round all intermediate values to two decimal places as needed.)
(c) decide which model is the better fit. choose the correct answer below.
the model $\boldsymbol{□}$ is the better fit because the equation of the line that has the $\boldsymbol{□}$ $\boldsymbol{□}$ is the better fit.

Explanation:

For model fit, a smaller sum of squared residuals indicates that the model's predicted values are closer to the actual data points, meaning it is a better fit. The sum of squared residuals for $y=1.18x+2.23$ is 15.80, which is smaller than 21.76 (the sum for $y=2x-4$).

Answer:

The model $\boldsymbol{y=1.18x+2.23}$ is the better fit because the equation of the line that has the smallest sum of squared residuals is the better fit.