Question

find the square. simplify your answer. $(4z + 1)^2$

Explanation:

Step1: Apply square of sum formula

Recall the formula $(a+b)^2 = a^2 + 2ab + b^2$, where $a=4z$, $b=1$.

Step2: Calculate each term individually

$a^2=(4z)^2=16z^2$, $2ab=2*(4z)*(1)=8z$, $b^2=1^2=1$.

Step3: Combine the terms

Add the calculated terms together.
$16z^2 + 8z + 1$

Answer:

$16z^2 + 8z + 1$