Question

find the sum.\\((2b^2 + b + 4) + (6b^2 - 3b + 1)\\)\\(?b^2 + \square b + \square\\)

Explanation:

Step1: Combine like terms for \(b^2\) terms

We have \(2b^2\) from the first polynomial and \(6b^2\) from the second polynomial. To combine them, we add their coefficients: \(2 + 6 = 8\). So the \(b^2\) term is \(8b^2\).

Step2: Combine like terms for \(b\) terms

The first polynomial has \(b\) (which is \(1b\)) and the second has \(-3b\). Adding their coefficients: \(1 + (-3) = -2\). So the \(b\) term is \(-2b\).

Step3: Combine constant terms

The first polynomial has a constant term of \(4\) and the second has \(1\). Adding them: \(4 + 1 = 5\). So the constant term is \(5\).

Answer:

\(8b^2 + (-2)b + 5\) (or simplified as \(8b^2 - 2b + 5\))