Question

find the sum or difference. ((5n - 2p^2 + 2np) - (4p^2 + 4n)) (square p^2 + square np + square n)

Explanation:

Step1: Distribute the negative sign

$(5n - 2p^2 + 2np) - 4p^2 - 4n$

Step2: Group like terms

$(-2p^2 - 4p^2) + 2np + (5n - 4n)$

Step3: Combine like terms

$-6p^2 + 2np + n$

Step4: Match to given structures

For $p^2$ term: $-6$
For $np$ term: $2$
For $n$ term: $1$

Answer:

$-6$, $2$, $1$
(To fill the blanks: $\boldsymbol{-6}$ in the $p^2$ blank, $\boldsymbol{2}$ in the $np$ blank, $\boldsymbol{1}$ in the $n$ blank)