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find the surface area and volume of the solid. round each measure to th…

Question

find the surface area and volume of the solid. round each measure to the nearest tenth, if necessary. need help with this question? volume. cm³ surface area cm²

Explanation:

Step1: Find the base - area of the triangular base

The base is a right - triangle with legs \(a = 2.0\mathrm{cm}\) and \(b = 2.4\mathrm{cm}\). The area of a right - triangle \(A_{base}=\frac{1}{2}\times a\times b\).
\[A_{base}=\frac{1}{2}\times2.0\times2.4 = 2.4\mathrm{cm}^2\]

Step2: Calculate the volume of the prism

The volume of a prism \(V=A_{base}\times h\), where \(h = 3.2\mathrm{cm}\).
\[V = 2.4\times3.2=7.68\mathrm{cm}^3\approx7.7\mathrm{cm}^3\]

Step3: Find the lengths of the sides of the triangular base

Using the Pythagorean theorem, the hypotenuse \(c\) of the right - triangle base: \(c=\sqrt{2.0^{2}+2.4^{2}}=\sqrt{4 + 5.76}=\sqrt{9.76}\approx3.12\mathrm{cm}\)

Step4: Calculate the surface area of the prism

The surface area of a triangular prism \(S = 2A_{base}+(a + b + c)h\).
\[S=2\times2.4+(2.0 + 2.4+3.12)\times3.2\]
\[S = 4.8+(7.52)\times3.2\]
\[S = 4.8+24.064\]
\[S=28.864\mathrm{cm}^2\approx28.9\mathrm{cm}^2\]

Answer:

Volume: \(7.7\mathrm{cm}^3\)
Surface Area: \(28.9\mathrm{cm}^2\)