Question

find the surface area of the wrapper around the can. round to the nearest whole number cm squared

Explanation:

Step1: Identify the radius and height

The diameter of the can is 3.5 cm, so the radius $r=\frac{3.5}{2}= 1.75$ cm, and the height $h = 11$ cm. The surface - area of the wrapper around the can is the lateral surface area of the cylinder, given by the formula $A = 2\pi rh$.

Step2: Substitute values into the formula

Substitute $r = 1.75$ cm and $h=11$ cm into the formula $A = 2\pi rh$. We get $A=2\times\pi\times1.75\times11$.

Step3: Calculate the result

$A = 2\times\frac{22}{7}\times1.75\times11$ (using $\pi=\frac{22}{7}$). First, $2\times\frac{22}{7}\times1.75=2\times22\times0.25 = 11$. Then $A=11\times11=121$ $cm^{2}$.

Answer:

121