Question

find the value of $c$ in $10 + c^2 = 74$.
$c = 8, c = -8$
$c = 2\sqrt{21}, c = -2\sqrt{21}$
$c = 8\sqrt{2}, c = -8\sqrt{2}$
$c = 6, c = -6$

Explanation:

Step1: Isolate $c^2$ term

Subtract 10 from both sides:
$c^2 = 74 - 10$
$c^2 = 64$

Step2: Solve for $c$

Take square root of both sides:
$c = \pm\sqrt{64}$
$c = \pm8$

Answer:

$c = 8, c = -8$