find the value of c. pythagorean theorem: $a^{2}+b^{2}=c^{2}$

$find the value of c. pythagorean theorem: $a^{2}+b^{2}=c^{2}$$

Let $a = 1$ m and $b = 4$ m.

According to $a^{2}+b^{2}=c^{2}$, we substitute the values: $c^{2}=1^{2}+4^{2}=1 + 16=17$.

$c=\sqrt{17}\approx 4.12$ m.

$c = \sqrt{17}\text{ m}\approx4.12\text{ m}$