Question

find the value of x in the triangle shown below. x = ° 14 14 50° 18 show calculator 4 of 4

Explanation:

Step1: Identify triangle type

Isosceles triangle with two sides=14, base=18.

Step2: Apply Law of Sines

\(\frac{14}{\sin50^\circ}=\frac{18}{\sin x}\)

Step3: Solve for \(\sin x\)

\(\sin x=\frac{18\sin50^\circ}{14}\approx\frac{18\times0.7660}{14}\approx0.9849\)

Step4: Find \(x\)

\(x=\arcsin(0.9849)\approx80^\circ\)

Answer:

80