Question

find the value of x in the triangle shown below. choose 1 answer. x = √32 x = √48 x = √80

Explanation:

Step1: Apply Pythagorean theorem

For a right - triangle with legs \(a\) and \(b\) and hypotenuse \(c\), \(c^{2}=a^{2}+b^{2}\). Here \(a = 4\), \(b = 8\), and \(x\) is the hypotenuse. So \(x^{2}=4^{2}+8^{2}\).

Step2: Calculate the right - hand side

\(4^{2}=16\) and \(8^{2}=64\), then \(4^{2}+8^{2}=16 + 64=80\). So \(x^{2}=80\).

Step3: Solve for \(x\)

Taking the square root of both sides, \(x=\sqrt{80}\).

Answer:

\(x=\sqrt{80}\)