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find wx in rectangle vwxy. w v 7a+32 a+68 x y 4a-5 wx =

Question

find wx in rectangle vwxy. w v 7a+32 a+68 x y 4a-5 wx =

Explanation:

Step1: Set equal opposite sides

In a rectangle, opposite sides are congruent, so $a+68 = 4a-5$.

Step2: Solve for $a$

Rearrange to isolate $a$:
$$68 + 5 = 4a - a$$
$$73 = 3a$$
$$a = \frac{73}{3}$$

Step3: Substitute $a$ into WX expression

WX is given by $7a+32$, so substitute $a=\frac{73}{3}$:
$$WX = 7\times\frac{73}{3} + 32$$

Step4: Calculate final value

Simplify the expression:
$$WX = \frac{511}{3} + \frac{96}{3} = \frac{607}{3}$$

Answer:

$\frac{607}{3}$