Question

find the x- and y-intercepts.
$x^2 = -y + 9$
write each intercept as an ordered pair.
if there is more than one intercept, use the \and\ button.
select
one\ if applicable.
part 1 of 2
x-intercept(s):

Explanation:

Step1: Find x-intercepts, set $y=0$

Substitute $y=0$ into $x^2=-y+9$:
$x^2 = -0 + 9$
$x^2 = 9$

Step2: Solve for x

Take square root of both sides:
$x = \pm\sqrt{9} = \pm3$

Step3: Find y-intercept, set $x=0$

Substitute $x=0$ into $x^2=-y+9$:
$0^2 = -y + 9$
$0 = -y + 9$

Step4: Solve for y

Rearrange to isolate y:
$y = 9$

Answer:

x-intercept(s): $(3, 0)$ and $(-3, 0)$
y-intercept: $(0, 9)$