Question

find the zeros of the function. enter the solutions from least to greatest. g(x) = (x - 2)(3x + 3) lesser x = -1 greater x = 2

Explanation:

Step1: Set function to zero

To find the zeros of \( g(x)=(x - 2)(3x + 3) \), we set \( g(x) = 0 \), so \( (x - 2)(3x + 3)=0 \).

Step2: Solve each factor

By the zero - product property, if \( ab = 0 \), then either \( a = 0 \) or \( b = 0 \).

• For the first factor: \( x-2 = 0 \), adding 2 to both sides gives \( x=2 \).
• For the second factor: \( 3x + 3=0 \). First, subtract 3 from both sides: \( 3x=-3 \). Then divide both sides by 3: \( x=\frac{-3}{3}=-1 \).

Answer:

lesser \( x=-1 \)
greater \( x = 2 \)