Question

follow the steps below to solve the following radical equation:
\\(\sqrt{3x - 2}+\sqrt{3x + 13}=3\\)
rewrite the equation to isolate one of the radical expressions. do not yet clear any radicals.

Explanation:

Step1: Isolate one radical term

We start with the equation $\sqrt{3x - 2}+\sqrt{3x + 10}=3$. Isolate $\sqrt{3x - 2}$ by subtracting $\sqrt{3x + 10}$ from both sides.
$\sqrt{3x - 2}=3-\sqrt{3x + 10}$

Answer:

$\sqrt{3x - 2}=3-\sqrt{3x + 10}$