Question

a football is kicked vertically upward from a height of 6 feet with an initial speed of 65 feet per second. the formula h = 6 + 65t - 16t^2 describes the balls height above the ground, h, in feet, t seconds after it was kicked. use this formula to find the balls height 3 seconds after it was kicked. the balls height, 3 seconds after it was kicked, was feet.

Explanation:

Step1: Substitute t = 3 into formula

$h = 6+65\times3 - 16\times3^{2}$

Step2: Calculate multiplications

$h=6 + 195-16\times9$
$h = 6+195 - 144$

Step3: Calculate sums and differences

$h=(6 + 195)-144$
$h = 201-144$
$h = 57$

Answer:

57