Question

four students are training for their cross - country team at school. they were told to run for as long as they could without stopping. the coach measured their total distances and their overall time. calculate the average speed for each student and find the two students who tied for the same average speed.
a bev and chris
b bev and leslie
c chris and dylan
d dylan and leslie

Explanation:

Step1: Recall speed formula

Speed $v=\frac{d}{t}$, where $d$ is distance and $t$ is time.

Step2: Calculate Leslie's speed

Leslie's distance $d = 10.8$, time $t = 100$. So $v_{Leslie}=\frac{10.8}{100}=0.108$.

Step3: Calculate Bev's speed

Bev's distance $d = 6.5$, time $t = 55$. So $v_{Bev}=\frac{6.5}{55}\approx0.118$.

Step4: Calculate Chris's speed

Chris's distance $d = 1.2$, time $t = 120$. So $v_{Chris}=\frac{1.2}{120}=0.01$.

Step5: Calculate Dylan's speed

Dylan's distance $d = 3.6$, time $t = 60$. So $v_{Dylan}=\frac{3.6}{60}=0.06$.

Since no two - calculated speeds are equal, there is likely an error in the problem - setup or data. But if we assume the data is correct as given, we have calculated the speeds as above.

Answer:

There is no correct option as no two students have the same average speed based on the calculations.