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Question
the function that passes through the points (-2, 6) and (2, 7).
Step1: Find the slope
The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \( m=\frac{y_2 - y_1}{x_2 - x_1} \). Here, \((x_1,y_1)=(-2,6)\) and \((x_2,y_2)=(2,7)\). So, \( m=\frac{7 - 6}{2-(-2)}=\frac{1}{4} \).
Step2: Use point - slope form
The point - slope form of a line is \( y - y_1=m(x - x_1) \). Let's use the point \((-2,6)\). Substitute \( m = \frac{1}{4} \), \( x_1=-2 \) and \( y_1 = 6 \) into the formula:
\( y-6=\frac{1}{4}(x + 2) \)
Step3: Simplify to slope - intercept form
Expand the right - hand side: \( y-6=\frac{1}{4}x+\frac{1}{2} \)
Add 6 to both sides. Since \( 6=\frac{12}{2} \), we have \( y=\frac{1}{4}x+\frac{1}{2}+\frac{12}{2}=\frac{1}{4}x+\frac{13}{2} \)
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The equation of the line is \( y=\frac{1}{4}x+\frac{13}{2} \) (or in standard form \( x - 4y=-26 \))