Question

the functions f and g are defined as follows.
$f(x)=4x^2 - x$ $g(x)=-5x - 1$
find $f(-3)$ and $g(6)$.
simplify your answers as much as possible.
$f(-3)=\square$
$g(6)=\square$

Explanation:

Step1: Calculate \( f(-3) \)

To find \( f(-3) \), substitute \( x = -3 \) into the function \( f(x) = 4x^2 - x \).
\[

$$\begin{align*} f(-3)&= 4(-3)^2 - (-3)\\ &= 4(9) + 3\\ &= 36 + 3\\ &= 39 \end{align*}$$

\]

Step2: Calculate \( g(6) \)

To find \( g(6) \), substitute \( x = 6 \) into the function \( g(x) = -5x - 1 \).
\[

$$\begin{align*} g(6)&= -5(6) - 1\\ &= -30 - 1\\ &= -31 \end{align*}$$

\]

Answer:

\( f(-3) = 39 \)
\( g(6) = -31 \)