Question

functions & tables - linear
given the function $f(x) = -3x - 2$ complete the table.

$x$	$f(x)$
$-2$
$0$
$2$

submit

Explanation:

Step1: Substitute \( x = -3 \) into \( f(x) \)

We have the function \( f(x) = -3x - 2 \). When \( x = -3 \), we substitute \( x \) into the function:
\( f(-3) = -3\times(-3) - 2 \)

Step2: Calculate the value

First, calculate \( -3\times(-3) = 9 \), then subtract 2: \( 9 - 2 = 7 \)

For \( x = -2 \):

Step1: Substitute \( x = -2 \) into \( f(x) \)

\( f(-2) = -3\times(-2) - 2 \)

Step2: Calculate the value

\( -3\times(-2) = 6 \), then \( 6 - 2 = 4 \)

For \( x = 0 \):

Step1: Substitute \( x = 0 \) into \( f(x) \)

\( f(0) = -3\times0 - 2 \)

Step2: Calculate the value

\( -3\times0 = 0 \), then \( 0 - 2 = -2 \)

For \( x = 2 \):

Step1: Substitute \( x = 2 \) into \( f(x) \)

\( f(2) = -3\times2 - 2 \)

Step2: Calculate the value

\( -3\times2 = -6 \), then \( -6 - 2 = -8 \)

Answer:

When \( x = -3 \), \( f(x) = 7 \); when \( x = -2 \), \( f(x) = 4 \); when \( x = 0 \), \( f(x) = -2 \); when \( x = 2 \), \( f(x) = -8 \)

Filling the table:

\( x \)	\( f(x) \)
\( -2 \)	\( 4 \)
\( 0 \)	\( -2 \)
\( 2 \)	\( -8 \)