Question

1. given 5.86 grams of nan₃, how many grams of na are produced?

Explanation:

Step1: Find molar mass of $\text{NaN}_3$

Molar mass of $\text{NaN}_3 = M(\text{Na}) + 3\times M(\text{N}) = 23\ \text{g/mol} + 3\times14\ \text{g/mol} = 65\ \text{g/mol}$

Step2: Calculate moles of $\text{NaN}_3$

$\text{Moles of }\text{NaN}_3 = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{5.86\ \text{g}}{65\ \text{g/mol}} \approx 0.0902\ \text{mol}$

Step3: Relate moles of $\text{NaN}_3$ to $\text{Na}$

From decomposition reaction $2\text{NaN}_3
ightarrow 2\text{Na} + 3\text{N}_2$, 1 mol $\text{NaN}_3$ produces 1 mol $\text{Na}$. So moles of $\text{Na} = 0.0902\ \text{mol}$

Step4: Calculate mass of $\text{Na}$

$\text{Mass of }\text{Na} = \text{Moles} \times \text{Molar Mass} = 0.0902\ \text{mol} \times 23\ \text{g/mol} \approx 2.07\ \text{g}$

Answer:

2.07 grams