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Question
given: $f(x) = 2x^2 - 4x + 10$ find: $f(-2)$ 26 -10 -26 10
Step1: Substitute \( x = -2 \) into \( f(x) \)
\( f(-2) = 2(-2)^2 - 4(-2) + 10 \)
Step2: Calculate each term
First, \( (-2)^2 = 4 \), so \( 2(-2)^2 = 2\times4 = 8 \).
Second, \( -4(-2) = 8 \).
Third, the constant term is \( 10 \).
Step3: Sum the terms
\( f(-2) = 8 + 8 + 10 = 26 \)
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