Question

7 given \\(\triangle xps \cong \triangle dnf\\), find the values of \\(x\\) and \\(y\\).

Explanation:

Step1: Match congruent sides for $x$

Corresponding sides of congruent triangles are equal. So $17x+3 = 57$.

Step2: Solve for $x$

Subtract 3 from both sides: $17x = 57 - 3 = 54$.
Divide by 17: $x = \frac{54}{17} \approx 3.18$

Step3: Match congruent sides for $y$

Corresponding sides of congruent triangles are equal. So $4y-3 = 51$.

Step4: Solve for $y$

Add 3 to both sides: $4y = 51 + 3 = 54$.
Divide by 4: $y = \frac{54}{4} = \frac{27}{2} = 13.5$

Answer:

$x = \frac{54}{17}$ (or approximately 3.18), $y = \frac{27}{2}$ (or 13.5)